Return the summation of the number smaller than n

Description: Write a function named findSmallerTotal that accepts an array and a number n, returns the summation of the number smaller than n.

function findSmallerTotal(arr, n) {
  let sum = 0;
  for (let i = 0; i < arr.length; i++) {
    if (arr[i] < n) {
      sum += arr[i];
    }
  }
  return sum;
}

console.log(findSmallerTotal([1, 2, 3], 3)); // 3
console.log(findSmallerTotal([1, 2, 3], 1)); // 0
console.log(findSmallerTotal([3, 2, 5, 8, 7], 999)); // 25
console.log(findSmallerTotal([3, 2, 5, 8, 7], 0)); // 0

The other answers:

function findSmallerTotal(arr, n) {
  let i = 0;
  let sum = 0;
  do {
    if (arr[i] < n) {
      sum += arr[i];
    }
    i++;
  } while (i < arr.length);
  return sum;
}

function findSmallerTotal(arr, n) {
  let i = 0;
  let sum = 0;
  while (i < arr.length) {
    if (arr[i] < n) {
      sum += arr[i];
    }
    i++;
  }
  return sum;
}